TITRATION OF AN ACID (A PREPARED STANDARD SOLUTION OF KH?O?C?) AGAINST A BASE (NAOH) USING PHENOLPHTHALEIN AS AN INDICATOR BY GRACE The aim of this experiment is to fake a cadence solution of potassium hydrogen phthalate (KH?O?C?) and then use it to calculate the submerging of atomic pattern 11 hydroxide by titrating the dit (KH?O?C?) against the curtain call (NaOH). Before the whole experiment could take place, some weapon were needed which included the following; A weighing balance, burette, pipette, a conical flask, clamp and then the setup was as to a lower place; THEORY To calculate for the moles of KH?O?C?, I utilize n (mol) =m (g)/M (gmol?? (JOHN immature AND SADRU DAMJI, PG 6 OF CHAPTER 1.THIRD EDITION). Whereby m= muss of the dit, M=molar mountain of the acid and n= twist of moles. Molar mass of KH?O?C? is 204.1g/mol and its mass is 1g accordingly=1g/204.1gmol?? n=0.0048996m ol except more, to calculate for the immersion of the acid, I use C(moldm?3.) =n (mol)/v (dm3) Whereby c= niggardness, n=number of moles and v=volume apply. (JOHN kilobyte AND SADRU DAMJI, PG 27.THIRD EDITION) Volume=0.1dm3 Concentration of acid =0.0048996mol/0.1dm3 =0.

049moldm?3 Also, to calculate for the sightly titre volume of the acid used, I summed up the three consistent values from my experiment and separate it by 3(sarps series, 2009) gum olibanum Average Titre volume= (19.60+19.60+19.60) 3 =19.60cm3 Also, to calculate for the concentra! tion of sodium hydroxide, I used The dilution factor, C?v?=C?v? (JOHN GREEN AND SADRU DAMJI pg28, third edition) whereby C?=concentration of the acid used=0.049moldm?3 v?=volume of acid used (titre volume) =19.60cm3 C?=concentration of the base, v?=volume of the base used=10cm3 Therefore C?= (0.049*19.60)/10 C?=0.096 moldm?3 Therefore the concentration of sodium hydroxide is0.096 moldm?3 |Burette...If you want to slip up up a full essay, order it on our website:
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